If l = log 5/7, m = log 7/9 and n = 2( log 3 - log √5) Find the value of L+m+n
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Step-by-step explanation:
given data,
l= log 5/7, m= log 7/9 & n= 2 (log 3 - log root over 5 )
now, l+m+n
substituting the values
=log 5/7 + log 7/9 + log 3^2 - log 5 [ since root of 5 means 5 to the power 1/2 & here '^' is power ]
= log (5/7 × 7 /9) + log 9 - log 5
= log 5 / 9 + log 9/5
=log ( 5/9×9 /5)
= log 1
= 0 ( since log 1 = 0)
answer......
I hope it's will help you.
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