if l, m, n, are three lines such that l paralell m and n perpendicular, then prove that n perpendicular m
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3
Answer:
let the gradient of lines l,m,n be
m_{l},m_{m},m_{n}
then, according to question,
m_{l}=m_{m}
and
m_{n}m_{l}=-1
so,
m_{n}m_{m}=-1
so n is perpendicular to m
Answered by
1
Step-by-step explanation:
Given: l, m, n are three lines such that l || m and n ⊥ l.
To prove: n ⊥ m
Proof :
Since, n ⊥ l
→ ∠1 = 90° ………….(1)
Now, l ‖ m and transversal intersects them.
∠2 = ∠1 ………(2)
Thus, the corresponding angles made by the transversal n with lines l and m are equal.
From eq (1) & (2) , we get ∠2 = ∠1 = 90°
→ ∠2 = 90°
Hence, n is perpendicular to m (n ⊥ m).
Figure of this answer is in the attachment below.
- Hope this help you !
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