Question

if lambda, beeta are zeroes of ( √3x ^ 2 + 2x + 1 / 7 ) ( lambda- beeta ) = ?​

Answer 1

Answer:

λ - β = √(4/3 - 4/7√3)

Step-by-step explanation:

√3x ^ 2 + 2x + 1 / 7

sum of roots = - b/a

product of roots = c/a

so,

λ + β = - 2/√3

λβ = 1/7√3

λ² + β² = (λ + β)² - 2λβ

λ² + β² = ( - 2/√3 )² - 2 × 1/7√3 = 4/3 - 2/7√3

now,

(λ - β)² = λ² + β² - 2λβ = 4/3 - 2/7√3 - 2/7√3

(λ - β)² = 4/3 - 4/7√3

λ - β = √(4/3 - 4/7√3)

Answer provided by Gauthmath.