Question

If (lamda not) threshold wavelength for photo electronic emission, (lamda not) is the wavelength of light falling on the surface of metal. If 'm' is the mass of electron, then the debroglie's wavelength of emitted electron is.?
1)[{h(lamda×lamda not)}/{2mc(lamda not-lambda)}]
2)[{h(lamda not-lambda)}/{2mc(lamda×lamda not)}]
3)[{h(lambda-lamda not)}/{2mc(lamda not×lambda)}]
4)[{h(lamda×lamda not)}/{2mc((lambda-lamda not))}]
_______________OBSERVE EVERY SINGLE LINE__________________
lambda not----->☆threshold wavelength ☆
lamda------------->☆wavelength ☆
h-------------------->☆planck's constant ☆
m-------------------->☆mass of electron☆
c--------------------->☆velocity ☆
(JEE MAIN QUESTION)DEDICATED FOR ALL SINCERE STUDENTS
@SHANKARMANISH
#JEEMAIN
/________________________SOLVE__________________________\​

Answer 1

Answer:

တျြိုငတုနနြတြသတဗနငန္နနနြနြငင

Explanation:

ငတြ၃ငမုမုမသစမ၄ညမသမနြနြဗ၃ငြ၃င၃

မ

မ

ယမုမငမင၃သ၃သသ၃သင၂၃နြနြဗမကမင၄ြ၄

မုမငငမငသနနငနန

နယနငနင၃ု၃ငသ၃၃

မ

န

န

နုနငနငငနသသ၂၃