If last term of ap is 5,3,1,-1 is -41 find the no of terms
Answers
Answered by
15
Answer:
24
Step-by-step explanation:
In APs nth term is given by a + ( n - 1 )d, where a is the first term and d is the common difference.
Here, let the number of terms be n.
First term = a = 5
Co. di. = d = 3 - 5 = - 2
⇒ - 41 = a + ( n - 1 )d
⇒ - 41 = 5 + ( n - 1 )( - 2 )
⇒ - 41 - 5 = ( n - 1 )( - 2 )
⇒ - 46 = ( n - 1 )( - 2 )
⇒ 46 = ( n - 1 )2
⇒ 23 = n - 1
⇒ 23 + 1 = 24 = n
Hence the required number of term is 24
Answered by
5
di. = d = 3 - 5 = - 2
⇒ - 41 = a + ( n - 1 )d
⇒ - 41 = 5 + ( n - 1 )( - 2 )
⇒ - 41 - 5 = ( n - 1 )( - 2 )
⇒ - 46 = ( n - 1 )( - 2 )
⇒ 46 = ( n - 1 )2
⇒ 23 = n - 1
⇒ 23 + 1 = 24 = n
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