Question

if law of conservation of mass holds good then predict how much residue would weight when 96 g of CaCO3 is heated and 12.2g of CO2 is released?

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Answer 1

Answer:

Explanationas per the law of conservation of mass the sum of reactants is always equal to sum of product similarly in this case also

reactants = product

that is

(4.2+10+2.2)g = 16.4g

if something in other form releases like if any reaction takes place and a kind of gas is produced then the weight of that gas will be the part of product only:

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Answer 2

Answer:

hey here it goes

Explanation:

CaCO3  → CaO + CO2

according to law of conservation of mass,

mass(CaCO3) = mass(CaO) + mass(CO2)

let, mass(CaO) = m

=> 96 g = m + 12.2 g

=> m = 83.8 g

hope it helps

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