Math, asked by rebel22, 9 months ago

if LCM a, 30 is equal to 45 and HCF a,30 is equal to 6 then find the value of a​

Answers

Answered by utu4sungh
12

Answer:

Step-by-step explanation:

HCF×lcm= product of two number

45×6=a×30

a=45×6/30

a=9

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Answered by sharonr
3

If LCM a, 30 is equal to 45 and HCF a, 30 is equal to 6 then value of a is 9

Solution:

Given that,

LCM of a and 30 is equal to 45

HCF of a and 30 is equal to 6

To find: value of a

We know that,

The product of LCM and HCF of any two given natural numbers is equivalent to the product of the given numbers

LCM \times HCF = product\\\\45 \times 6 = a \times 30\\\\5a = 45\\\\a = 9

Thus the value of a is 9

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