Question

if lcm and hcf of two numbers are 162 and 9 respectively .prime factors of the product of two numbers is?

Answer 1

Answer:

LCM is 162

HCF is 09

as we know that the product of HCF and LCM = prime factor of the product of two numbers .

so , 162×9 = 1458 .

1458= 2×3×3×3×3×3×3 .

sure this answer will help u .

Answer 2

Given:

LCM = 162

HCF = 9

To find :

The prime factors of the product of two numbers.

Solution:

Step 1 of 2:

Product of LCM and HCF of any two numbers is equal to the product of two numbers.

Product of LCM and HCF = 162 × 9

Product of LCM and HCF = 1458

Step 2 of 2:

The product of two numbers is 1458

The prime factors of 1458 are 2 × 3 × 3 × 3 × 3 × 3 × 3

Final answer:

Prime factors of the product of two numbers that is 1458 are $2^{1}$ , $3^{6}$ .