if length is 5 more tan breadth and area of rectangle is 2443518msq find its perimeter.
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Let the breadth be X metres, then length would be five more than the breadth, that is (X+5) metres.
Area of the rectangle is given as 2443518 m².
ATQ:-
=>L×B=2443518
=>X×(X+5)=2443518
=>X²+5X-2443518=0
=>X=-5+√9774072/2
=>X=1560.67
So, length=(X+3)m=1563.67 m
Breadth=X m=1560.67 m
Now, the perimeter of a rectangle=2×(L+B)
=2×(1563.67+1560.67)
=2×3124.34
=6248.68 m
So, the perimeter of this rectangle=6248.68 m
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