If length of a rectangle increased by 15% and width is down by 10 % find the percentge change in its area
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from new area the answer is here.. in the pic it is wrong.
new area = (23x/20)(9y/10)
=207xy/200
% increase=[ (207xy/200)- (xy) /xy] ×100
(207xy- 200xy) /200× (1/xy)× 100
=7/200 × 100
=7/2
3.5%
formula used for %increase is =
[(new value -original value)/ original value] × 100
new area = (23x/20)(9y/10)
=207xy/200
% increase=[ (207xy/200)- (xy) /xy] ×100
(207xy- 200xy) /200× (1/xy)× 100
=7/200 × 100
=7/2
3.5%
formula used for %increase is =
[(new value -original value)/ original value] × 100
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