Question

if length of a rectangle is 7 more than its breadth and its perimeter is 30 m then find its length and breadth​

Answer 1

GIVEN :

Length of Rectangle is 7 more than its breadth.

Let the Breadth of Rectangle be x

Length of the Rectangle be x + 7

Perimeter of Rectangle = 2 ( l + b ) = 30m

According to the problem,

2 ( x + x + 7 ) = 30

2 ( 2x + 7 ) = 30

2x + 7 = 30/2

2x + 7 = 15

2x = 15 - 7

2x = 8

x = 8/2

x = 4m

Breadth = x = 4m

Length :

= x + 7

= 4 + 7

= 11cm

Therefore, the length and breadth of Rectangle are 11m and 4m respectively.

Answer 2

$\underline{\underline{\mathfrak{\green{Answer:-}}}}$

Length = 11m

Breadth = 4m

$\underline{\underline{\mathfrak{\green{Explanation:-}}}}$

$\underline{\pink{Given}}$

Length of the recrangle is 7 more than its breadth

perimeter of rectangle = 30m

$\underline{\pink{To \:Find}}$

Length and breadth of rectangle

$\underline{\pink{Solution}}$

Let,

Breadth (b)= x

Length (l)= x+7

As we know,

$\boxed{\red{Perimeter\: of\: rectangle = 2(l+b)}}$

Now,

2(l+b) = 30

l+b = $\dfrac{30}{2}$

x+7+x = 15

2x +7 = 15

2x = 15-7

2x = 8

x = $\dfrac{8}{2}$

x = 4

_____________________

breadth (b) = x

b = 4

Length (l) = x+7

l = 4+7

l = 11

Hence,

length and breadth of the triangle are 11m and 4m respectively!