if length of open pipe is 50 cm , the lowest frequency will be
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there are two types of organ pipes ; open organ pipe and closed organ pipe. in case of open pipe, both end are open and in case of closed pipe, one end is close and other end is open.
see diagram, here it is clearly shown, propagation of stationary waves in open pipe. waves form two antinodes at both ends and one node at midpoint of pipe.
so, length of pipe = λ/4 + λ/4
or, 50cm = λ/2
or, λ = 100cm = 1m
hence, lowest frequency will be , f = v/λ
= v/1 m
= v Hz , here v is speed of wave.
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