If lengths of diagonals of rombus are 24 and 32 cm respectively find its perimeter
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80 CM
Step-by-step explanation:
LENGTH OF DIAGONAL 1=24 CM
LENGTH OF DIAGONAL 2=32 CM
PERIMETER FORMULA OF RHOMBUS=2√(D1)^2+(D2)
=2*√24^2+32^2
=2*√576+1024
=2*√1600
=2*40
=80CM
PLS MARK AS BRAINLIEST..........
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