Question

if line ab and de are parallel find the value of bca​

Answer 1

Answer:

$cba = 40 \: transversal \: to \: cbe \\ \\ sum \: of \: angles \: of \: a \: triangle \: = 180 \\ = > 40 + 36 + bca = 180 \\ bca = 180 - 76 \\ = > bca = 104$

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Answer 2

Answer:

• 104° is the measure of ∠BCA.

Step-by-step explanation:

Given :

In the figure, line AB and DE are parallel.

∠EDB = 40° & ∠CAB = 36°.

To find :

Value of ∠BCA.

Solution :

We see,

∠EDB = ∠CBA = 40°

• [∵ Alternate interior angles are equal]

Now,

In ΔCAB.

• Angle sum property.

⇒ ∠BCA + ∠CBA + ∠CAB = 180°

⇒ ∠BCA + 40° + 36° = 180°

⇒ ∠BCA + 76° = 180°

⇒ ∠BCA = 104°

∴ Measure of ∠BCA is 104°.