Question

If line segments DA,CB and OM perpendicular
on segment AB, where O is the intersecting points
for line segments AC and DB, If OA =2.4 cm
and OC =3.6 cm, then find out.
AM
(1)
BM
(i) If BO =3cm, find the value of DO.​

Answer 1

Answer:

In a right triangle BAD,

We have OM parallel to side DA of triangle BAD. So triangle BMO is similar to triangle BAD by AA similarity criteria.

Thus corresponding sides of similar triangles are proportional.

Thus, OM÷AD = BM÷AB, which implies, OM÷2.4 = BM÷AB ...........(1)

In the same way, triangle ABC is similar to triangle AMO.

Thus, we have OM÷3.6 = AM÷AB .........(2)

(1)+(2) gives (OM÷2.4)+(OM÷3.6)=(BM÷AB)+(AM÷AB)

On simplifying this,

we get OM = (3.6 × 2.4) ÷ 6 = 1.44 cm

Answer 2

Answer:

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Step-by-step explanation: