If linear momentum (P) of a moving object varies
with time(t) is given as 3 2 Ptt = ++ (2 3 2) kg m/s
(where t is in second), then force acting on the
object at t = 1 s will be
(1) 6 N (2) 12 N
(3) 9 N (4) 18 N
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1
Answer:
F
x
=
dt
dP
x
=4t⟹F
x
=4(2)=8
F
y
=
dt
dP
y
=3t⟹F
y
=3(2)=6
F=
F
x
2
+F
y
2
=
8
2
+6
2
=
64+36
=
100
=10
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