Question

If log, 0.5 = 1.6990 then the number of zeros that are between the decimal
point and first significant figure

$(0.5) {100}$
Is...


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Answer 1

Answer:

Let N=(61)200

Taking log both side on base 10.

logN=200log61=−200log6=−200(log2+log3)=−200(.301+.477)=155.6

Hence, number of required cyphers =155