Question

If log 108 - log 176- log X + log 396 - log 81= 0 then find the values of X

Answer 1

Value of x is 3

Step-by-step explanation:

Given,

log108 - log176 - logx + log396 - log81 = 0

or, logx = log108 - log176 + log396 - log81

or, logx = (log108 + log396) - (log176 + log81)

or, logx = log(108 * 396) - log(176 * 81)

or, logx = log{(108 * 396) / (176 * 81)}

or, logx = log(42768/14256)

or, logx = log3

Then x = 3

Therefore the required solution is

x = 3

Logarithmic rules:

• log(ab) = loga + logb

• log(a/b) = loga - logb

• loga = logb gives a = b

Note:

To solve this type of problems, do remember to take the constantly terms to one side and use the logarithmic formuae for products and divisions.