Question

factorise 8a3+27b3 by using identity. please answer my question I will mark you as brainliest​

Answer 1

Answer:

$(2a + 3b)( {2a}^{2} - 2a \times 3b + {3b}^{2} )$

Step-by-step explanation:

⇛${8a}^{3} + 27 {b}^{3} = 0$

⇛$( {2a})^{3} + ({3b})^{3} = 0$

⇛$(2a + 3b)( {2a}^{2} - 2a \times 3b + {3b}^{2} )$

⤴⤴⤴⤴⤴⤴This is derived From a Formula !! and it is only your answer.

That formula is :-

${a}^{3} + {b}^{3} = ( a + b)( {a}^{2} - ab + {b}^{2} )$

Now, Let's go more deep for the final solution !!

$(2a + 3b)( {2a}^{2} - 6ab + 3 {b}^{2} )$Here Multiply the (2a²-6ab+3b²) by one by one. firstly multiply with 2a then after secondly do it with 3b .

After Evaluation We will Get value

:- 8a³+27b³ which is called verification.

Answer 2

Answer:

(2a+3b)(2a^2-2a×3b+3b^2)