Question

If log 2=0.3010 and logb3=0.4771 Find the value of log 48

Answer 1

Answer:

Step-by-step explanation:

log 48 = log (16X3) = log 2^4 + log 3 = 4 log 2 + log 3 = 4(0.3010)+0.4771

                                                              =1.204+0.4771

                                                              = 1.6811