Question

If log 2=0.30103 then how many digits are there in 2 power 15?​

Answer 1

Step-by-step explanation:

Given log

10

2=0.301

log

10

2

64

=64×log

10

2=64×0.3010=19.264

⇒2

64

=10

19.264

The number of digits in 10

19

is 20 , there will be 21 digits from 10

21

The number 10

19.264

lies between them

Therefore the number of digits in 10

19.264

is 20

Therefore the correct option is D

$</p><p></p><p> </p><p>Given log </p><p>10</p><p></p><p> 2=0.301</p><p>log </p><p>10</p><p></p><p> 2 </p><p>64</p><p> =64×log </p><p>10</p><p></p><p> 2=64×0.3010=19.264</p><p>⇒2 </p><p>64</p><p> =10 </p><p>19.264</p><p> </p><p>The number of digits in 10 </p><p>19</p><p> is 20 , there will be 21 digits from 10 </p><p>21</p><p> </p><p>The number 10 </p><p>19.264</p><p> lies between them</p><p>Therefore the number of digits in 10 </p><p>19.264</p><p> is 20</p><p>Therefore the correct option is D</p><p>$