if log 2 is equals to 0.3010 and log 3 is equals to 0.4771 find the value of log 12
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Answered by
2
Answer:
the value of log12 is 1.079
Answered by
5
Answer:
LOG12= log4×3
log4+log3
log2²+log3
2log2+log3
2(0.3010)+(0.4771)
= 0.6020+0.4771
= 1.0791
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