Math, asked by jatinlucky, 10 months ago

In a cartesian plane, draw a quadrilateral whose vertices are A(4,3), B(-4,3), C (-4,-3)and D(4,-3)
Draw its diagonals and write the coordinates of the point where the diagonals cut each other.​

Answers

Answered by amitnrw
18

a quadrilateral whose vertices are A(4,3), B(-4,3), C (-4,-3)and D(4,-3) Diagonals cit  each other at 0,0 coordinates

Step-by-step explanation:

A quadrilateral whose vertices are A(4,3), B(-4,3), C (-4,-3)and D(4,-3)

has been drawn

This is an rectangle with Sides 8  & 6

AB = √(-4 - 4)² + (3 - 3)² = 8

BC = √(-4 -(- 4))² + (-3 - 3)² = 6

CD = √(-4 - 4)² + (-3 - 3)² = 8

DA = √(4 - 4))² + (-3 - 3)² = 6

Diagonal intersect at Origin

As Diagonals of Rectangle bisect each other

Diagonal intersection point =  Midpoint of AC   or Mid point of BD

Midpoint of AC  = ( 4 - 4)/2 , (3 - 3)/2 = 0, 0

Midpoint of BD  = (  4 - 4)/2 , (3 - 3)/2 = 0, 0

0,0 are coordinates of the point where the diagonals cut each other

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