If log 8=0.90find the value of log 0.125
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Log8=0.9
3log2=0.9
log2=0.3
log.125=?
log(125x 10⁻³)
log125 +log10⁻³
3log5-log10
-3(log5/10)
-3(log1/2)
-3(log1-log2)
-3(0-log2)
3log2=log8=0.9
3log2=0.9
log2=0.3
log.125=?
log(125x 10⁻³)
log125 +log10⁻³
3log5-log10
-3(log5/10)
-3(log1/2)
-3(log1-log2)
-3(0-log2)
3log2=log8=0.9
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