If log a 6 = x and log a 3 = y then find the value of log a a⎯2 in terms of x and y
muthyamsaimadhuri:
its log a/2 to the base a
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1
Answer:
x - y
Step-by-step explanation:
x = logₐ 6
y = logₐ 3
logₐ 2
= logₐ ( 6 / 3 )
= logₐ 6 - logₐ 3
= x - y
these answer is wrong
Ah. I see the clarification on what was meant by the question. It wasn't log_a 2 that was wanted, but log_a (a/2). Okay...
This is just log a - log 2 (all logs base a) = 1 - log 2 = 1 - x + y (log 2 is already done above). So 1 - x + y is your answer.
This is just log a - log 2 (all logs base a) = 1 - log 2 = 1 - x + y (log 2 is already done above). So 1 - x + y is your answer.
no my answer and correct answer is 0 - x - y
Hmmm. You seem to have a problem.
log(a/2) = log(3a/6) = log 3 + log a - log 6 = y + 1 - x = 1 - x + y.
It can't be simpler.
log(a/2) = log(3a/6) = log 3 + log a - log 6 = y + 1 - x = 1 - x + y.
It can't be simpler.
hey I am typing the answer you see
I just typed it in the comment above. One line!
tnq i got it
Ok no problem
Answered by
0
log a 6=x log a 3=y
log a a - 2
1 - 2 **** (log a a = 1)
multiply with log base a
log base a (1-2)
log a 1 - log a 2
0 - log a 6/3 ****(log a 1 = 0)
0-log a 6 - log a 3
***0-x-y***
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