If log (a+b)=log a +log b find a in terms of b
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Answered by
60
log(a+b)=log a + log b
log(a+b)=log ab according to logarithm log m + log n = logmn
log gets cancelled
a+b=ab
b=ab-a
b=a(b-1)
b/a=b-1
b/a+1=b
b+a/a=b
log(a+b)=log ab according to logarithm log m + log n = logmn
log gets cancelled
a+b=ab
b=ab-a
b=a(b-1)
b/a=b-1
b/a+1=b
b+a/a=b
Answered by
3
Hence, a = b/(b - 1).
Given:
log (a + b)=log a +log b
To Find:
The value of 'a' in terms of 'b'.
Solution:
We have been given that
log (a + b) = log a +log b ...................................(I)
To solve this problem, we will be applying the product rule of logarithms, which states that the logarithm of a product is equal to a sum of logarithms.
Hence if 'a' and 'b' are two numbers, then
log(ab) = log a +log b ...................................(II)
From equations (I) and (II) we have
log (a + b) = log(ab)
by taking antilog on both sides
⇒ a + b = ab ......................... (by taking antilog on both sides)
Dividing both sides by a, we get
1 + b/a = b
⇒ b/a = b - 1
⇒ a = b/(b - 1)
Hence, a = b/(b - 1).
#SPJ3
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