If log (a-b)=log2+½loga+½logb then prove that a/b+b/a=6
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formula used
log(a) + log(b) = log (ab)
m log (a) = log (a^m)
log (a) = log (b)
implies that a = b
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log (a-b)=log2+½loga+½logb then prove that a/b+b/a=6
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