Question

If log base 2x^2 (1+ x^2) = 1, then find x.​

Answer 1

Answer:

1

Step-by-step explanation:

log base 2x^2 (1+ x^2) = 1

First we will have convert into exponential form,

we get as

(2x^2)^1= 1+ x^2

2x^2= 1+ x^2

1=2x^2-x^2

1= x^2x = √1 = 1

Hence we get as 1

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Answer 2

Given,

$log base 2x^2 (1+ x^2) = 1,$

To find,

We need to find the value of x

Solution,

The value of x $= +1$ or x $= -1$

First, we will have the equation given  in the question in exponential form

$(2x^2)^1= 1+ x^2$

$2x^2= 1+ x^2$

$1=2x^2-x^2$

$1= x^2x$

$=$√$1$

which can be either $+1 or -1$

Therefore, the value of x $= +1$ or x $= -1$

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