If log(m+n)=log m+log n show that m= n/n-1
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log (m+n) = log m + log n
log (m+n) = log (mn)
m+n = mn
n = mn - m
n = m(n-1)
n/(n-1) = m
log (m+n) = log (mn)
m+n = mn
n = mn - m
n = m(n-1)
n/(n-1) = m
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