If log (m+n) = log m + log n, show that m = n /(n-1)
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log(m+n)=logm+logn
or, log(m+n)=log mn
or, m+n=mn
or, (m+n)/m=n
or, 1+n/m=n
or, n/m=n-1
or, 1/m=(n-1)/n
or, m=n/(n-1) (proved)
or, log(m+n)=log mn
or, m+n=mn
or, (m+n)/m=n
or, 1+n/m=n
or, n/m=n-1
or, 1/m=(n-1)/n
or, m=n/(n-1) (proved)
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