if log n base 10= 3.15642, then the number of digits in n .
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Suppose that n has d digits; then 10d−1≤n<10d, because 10d is the smallest integer with d+1 digits. Now take logs base 10: log1010k=k, so the inequality becomes d−1≤log10n<d. If you now take the floor (= integer part) of log10n, throwing away everything to the right of the decimal point, you get ⌊log10n⌋=d−1. Thus, d=⌊log10n⌋+1. This isn’t quite what you posted, but it’s the integer part of it, and clearly the number of digits must be an integer.
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Answer:
The answer is 4
n=4
Hope this helps you!!!
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