Question

If log (p² + 36) = 2, Find the value of ​

Answer 1

$log \: ( {p}^{2} + 36) = 2$

${p}^{2} + 36 = antilog \: (2)$

${p}^{2} + 36 = 100$

${p}^{2} = 100 - 36$

${p}^{2} = 64$

$p = \sqrt{64}$

$p = 8$