if log(x^2y^3)=a & log (x/y)= b ,find log x & log y in terms of a & b
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log (x^2y^3)=a
=> logx^2 + logy^3=a
=> 2logx+ 3logy=a --------------(1)
again,
log (x/y)=b
=> logx-logy=b ----------------(2)
now ,
solve both equation (1) and (2)
hence ,
logx=(a+3b)/5
and put logx value in equation (1)
logy =(a-2b)/5
=> logx^2 + logy^3=a
=> 2logx+ 3logy=a --------------(1)
again,
log (x/y)=b
=> logx-logy=b ----------------(2)
now ,
solve both equation (1) and (2)
hence ,
logx=(a+3b)/5
and put logx value in equation (1)
logy =(a-2b)/5
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