Question

If log x = log 3 + 2 log 2- (3/4) log 16. the value of x is:

Answer 1

Logx= log 3 + 2 log 2- (3/4) log 16.

= log3+log4- log 16^3/4

=log3+log4-log2^12/4

=log3+log4-log2³

=log(3*4/8)

=log(3/2)

Logx=log3/2

x=3/2

Answer 2

Step-by-step explanation:

log x=log 3+2log2-(3/4)log 16

log x= log 3+ 2 log 2 - (3/4)log 16.

log x = log 3 + 2 log 2 - (3/4) log 2^4.

log x = log 3 + 2 log 2 - (3*4)/4 log 2.

log x = log 3 + 2 log 2 - 3 log 2.

log x = log 3 - log 2.

log x = log 3/2.

Therefore, by equating, x = 3/2.