Math, asked by Vaskhar10, 10 months ago

if log x/ry-qz=log y/pz-rx=log z/qx-py

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Answers

Answered by PrachiVakshi
8

Answer:

Step-by-step explanation:

log x/(ry-qz)=log y/(pz-rx)=log z/(qx-py)=k

log x =k(ry-qz)

log y=k(pz-rx)

log z=k(qx-py)

x^p*y^q*x^r=A

=> log x^p*y^q*z^r=log A

=>log x^p + log y^q + log z^r = log A

=>p log x + q log y + r log z = log A

=>pk(ry-qz) + qk(pz-rx) + rk(qx-py)=log A

k (pry-pqz+pqz-qrx+qrx-pry)=log A

=>k * 0=log A

=>A=10^0

=>A=0

.°. x^p * y^q * z^r=1

Hence Proved

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