If Log x to the base 3=log 16 to the base 9 then the value of x+1
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2 log is correct bye this is the correct answer
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Log x to the base 3=log 16 to the base 9
or, (log x to the base 1) (log 1 to the base 3) =(log 16 to the base 1) (log 1 to the base 3^2)
or, (log x to the base 1) (log 1 to the base 3) =(log 16 to the base 1) 2 (log 1 to the base 3)
or, (log x to the base 1) =2/(log 1 to the base 4^2)
or, (log x to the base 1) =2/{2(log 1 to the base 4) }
or, (log x to the base 1) =1/(log 1 to the base 4) , [since, log a to the base b=(1/log b to the base a) ]
or, (log x to the base 1) =(log 4 to the base 1)
comparing,we get x=4 .
Answer is x+1=4+1=5
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