If log(x+y/2) = 1/2(log x+log y) show that x=y
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log(x + y/2) = 1/2 log x+logy
log(x/2+Y/2) = log x^1/2+logy^1/2
log(x/2+Y/2) = log (xy)^1/2
x/2+Y/2 = (xy)^1/2
X^2/4+Y^2/4+xy/2 =xy
X^2/4+y^2/4-xy/2 = 0
(x/2-y/2)^2 = 0
x/2-y/2 = 0
x/2 =y/2
x=y
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log(x/2+Y/2) = log x^1/2+logy^1/2
log(x/2+Y/2) = log (xy)^1/2
x/2+Y/2 = (xy)^1/2
X^2/4+Y^2/4+xy/2 =xy
X^2/4+y^2/4-xy/2 = 0
(x/2-y/2)^2 = 0
x/2-y/2 = 0
x/2 =y/2
x=y
Thank you
plz mark me as a brainlest
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