if log(x+y/3)=1/2 ( log x + log y ) show that ( x-y )2 = 5xy
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Consider both sides of given equation
2log(x+y)=log5+logx+logy
log(x+y)²=log(5xy)
Cancel log on both the sides and expand bracket square of x+y
x²+2xy+y² = 5xy
x²+y² = 3xy
x²-2xy+y² = xy
(x-y)²=xy
Take log on both sides
log(x-y)²=logxy
2log(x-y)=logxy
log(x-y)=1/2(logxy)
log(x-y)=1/2(logx+logy)
This is the proof.
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