if log (x+y/4)=1/2 log x + 1/2 log y, show that x/y + y/x= 7
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log(x+y/3)=logx^1/2+logy^1/2
log(x+y/3)=log(xy)^1/2
x+y/3=(xy)^1/2
square on both sides
x^2+y^2=9xy-2xy
x^2/xy+y^2/xy=7
x/y+y/x=7
therefore proved
i guess it helped
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