Question

If log(x+y)=log(3x-3y÷2) then logx-logy=​

Answer 1

Answer:

log(x + y) = log((3x - 3y)/2)

x + y = (3x - 3y)/2

2(x + y) = 3x - 3y

2x + 2y = 3x - 3y

5y = x

log 5y = log x

log 5 + log y = log x

Step-by-step explanation:

i hope that helps you