if log x/y+z = log y/z+x = log z/x+y then prove that (x/y)^z*(y/z)^x*(z/x)^y = 1.
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Answer:
Correct option is
B
x
x
.y
y
.z
z
=1
Let
y−z
logx
=
z−x
logy
=
y−z
logz
=k
Now,
xlogx+ylogy+zlogz=k[x(y−z)+y(z−x)+z(y−z)]
⇒logx
x
+logy
y
+logz
z
=0
⇒logx
x
y
y
z
z
=0
⇒x
x
y
y
z
z
=1
Thus the correct answer is option B
Step-by-step explanation:
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