if log xbase3=4,logxbasey=4 theny=
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Answered by
0
Answer: y= 3
Step-by-step explanation:
log xbase3=4, and logxbasey=4,
Formula, log m base n= logm/logn
So, log xbase3=4
log x/ log 3=4, logx = 4× log3
Also, logxbasey=4
log x / log y= 4
Putting value of log x = 4× log3, we get
4× log3/ logy= 4, on solving we get,
log you = log 3
So, y= 3
Answered by
2
Answer:
y = 3
Note:
★ If log_b(N) = n , then N = aⁿ
★ log(a•b) = loga + logb
★ log(a/b) = loga - logb
★ log(Nⁿ) = n•(logN)
★ log_b(a) = loga / logb
Solution:
Given:
log_3(x) = 4 -------(1)
log_y(x) = 4 --------(2)
To find: y = ?
From eq-(1) and (2) , we have ;
=> log_3(x) = log_y(x)
=> logx / log3 = logx / logy
=> 1/log3 = 1/logy
=> logy = log3
=> y = 3
Hence,
The required value of y is 3 .
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