Question

If log16(log2a) = log4b, then 2^b² is : ?​

Answer 1

Answer:

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log16(log2a) = log4b

To Find:

2^b² - ?

Step by Step:

$log( \frac{x - y}{3} ) = \frac{1}{2}(logx + log \: y)$

$log( \frac{x - y}{3} ) = \frac{1}{2} log(xy)$

$2log( \frac{x - y}{3} ) = log \: xy$

$log ( { \frac{x - y}{3} })^{2} = log \: xy$

$( { \frac{x - y}{3} })^{2} = xy$

✪Log in a one-one Function:-

$\frac{ {x}^{2} + {y}^{2} - 2xy }{9} = xy$

${x}^{2} + {y}^{2} = 11xy$

Answer 2

Step-by-step explanation:

$hope \: it \: will \: help \: u$