If log2=0.3010 and log3=0.4771 then calculate log2.4
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Answer:
log2.4= 0.6131
Step-by-step explanation:
log(2.4)= log(3-0.6)=log(3)/log(0.6)= log(3)*log(10)/log(2*3)
log(3)*log(10)/log(2)+log(3)
by substituting the value we get log(2.4)=0.6131
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