If log2 =0.30103 & log3 = 0.47712 then the value of log7 is?
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Answered by
20
Answer:
4log7 = log7^4 = log2401 =log2400
= log100 + 3log2 + log3
= 2+ 0.90309 + 0.47712 = 3.38021
Therefore, log7 = 3.38021/4 = 0.8451.
✔️Hope it will help you.✔️
Answered by
5
Answer:4log7 = log7^4 = log2401 =log2400
= log100 + 3log2 + log3
= 2+ 0.90309 + 0.47712 = 3.38021
Therefore, log7 = 3.38021/4 = 0.8451.
Explanation:
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