Math, asked by swapnali01, 9 months ago

If log2 = .30103, log3 = .47712, log7 = .84510, then find the logarithms
of the following numbers-

(iii) (0.405) ^1/2​

Answers

Answered by nagathegenius
3

Answer:

Step-by-step explanation:

LOG .405 ^1/2

1/2 LOG .405

1/2(LOG 405/1000)

1/2(LOG 405 - 3 )

1/2(LOG 4.05 - 1 )

1/2(.6055-1 )

1/2(-0.3945)

-0.19725

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