Question

If log2 (x-3)=3, find x​

Answer 1

Answer:

The value of X is 6 .......

Step-by-step explanation:

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Answer 2

Given :

$\sf log_{2}(x - 3) = 3$

To find :

• the value of x

Solution :

$\sf \implies log_{2}(x - 3) = 3$

We know that :-

$\sf if \: log_{a}(b) = n \\ \sf then \: \: b = {a}^{n}$

$\sf \implies x - 3 = {2}^{3}$

$\sf \implies x - 3 = 2 \times 2 \times 2$

$\sf \implies x - 3 = 8$

$\sf \implies x = 8 + 3$

$\sf \implies x = 11$

Answer :

• value of x = 11

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$\bf \red{Additional-Information : }$

$\sf log_{e}( {a}^{b} ) = b \times log_{e}( {a})$

$\sf log_{e}( {a} \times b ) = log_{e}( {a}) + log_{e}( b )$

$\sf log_{e}( \dfrac{a}{b} ) = log_{e}( {a}) - log_{e}( b )$

$\sf log_{e}( e) = 1$

$\sf log_{e}( {a}) + log_{e}( b ) = log_{e}( {a} \times b )$

$\sf log_{e}( {a}) - log_{e}( b ) = log_{e}( \dfrac{a}{b} )$