Question

If log2 (x) – log2 (x - 1) = 5, then x is​

Answer 1

Answer:

$log_{2}(x) - log_{2}(x - 1) = 5 \\ log_{2}( \frac{x}{x - 1} ) = 5 \\ \frac{x}{x - 1} = {2}^{5} \\ \frac{x}{x - 1} = 32 \\ x = 32(x - 1) \\ x = 32x - 32 \\ 31x = 32 \\ \boxed{x = \frac{32}{31} }$

• x=32/31 is the right answer.