If log2(x²-4x+7)=2 find the value of x
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Step-by-step explanation:
2(x^2-4x+7)=2
x^2-4x+7=1
x^2-4x=(-6)
x(x-4)=(-6)
x=(-6)/x-4
x^2=3/2
x^2=6/6
x=1
Hope you happy with this answer.
Answer by priyanka
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