Question

If log2x-log2(x-1)=1 then'x'solve

Answer 1

we know that log a - log b = log $\frac{a}{b}$

⇒ $log_2{x}-log_2{x-1}=1$

⇒ $log_2{ \frac{x}{x-1}}=1$

⇒ $\frac{x}{x-1}=2$

⇒ x = 2x - 2 

⇒ x = 2 ANSWER